In this program, the user entered one integer value and it will find reverese of that number. #include <iostream> using namespace std; int main() { int no, rev = 0, rem; cout << "Enter an integer value: "; cin >> no; while(no != 0) { rem = no%10; rev = rev*10 + rem; no /= 10; } cout << "Reversed Number = " << rev; return 0; } OutPut Enter an integer value: 31122000 Reversed number = 00022113
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Here, First we take one number from user and assign it to temporary variable called temp. Now we execute on while loop until number is zero. Inside loop we get the last digit of the number by finding the reminder of the number by performing the modulus by 10, after that we append the digits with the formula rev=(rev*10)+reminder; first time the value of rev is 0. Now we remove last digit which is appended by performing division by 10. Now when loop completely executed the variable rev gives use reverse number. import java.util.*; public class reverse { public static void…